100x^2-10=54

Solution for 100x^2-10=54 equation:

100x^2-10=54

We move all terms to the left:

100x^2-10-(54)=0

We add all the numbers together, and all the variables

100x^2-64=0

a = 100; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·100·(-64)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*100}=\frac{-160}{200}
=-4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*100}=\frac{160}{200}
=4/5
$